A gas expands from 3, dm^3 to 5.8, dm^3 again | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The work done during expansion is given by $w = -P_{ext} 	imes \Delta V$. Given $P_{ext} = 3\, bar$ and $\Delta V = (5.8 - 3)\, dm^3 = 2.8\, dm^3

Vedclass · Accepted Answer

$295$

Vedclass · Answer

(D) The work done during expansion is given by $w = -P_{ext} 	imes \Delta V$. Given $P_{ext} = 3\, bar$ and $\Delta V = (5.8 - 3)\, dm^3 = 2.8\, dm^3$. $w = -3\, bar 	imes 2.8\, dm^3 = -8.4\, bar\, dm^3$. Since $1\, bar\, dm^3 = 100\, J$,$w = -8.4 	imes 100 = -840\, J$. The magnitude of work done is $840\, J$,which is used to heat the water. The heat absorbed by water is $q = m 	imes c 	imes \Delta T$. Mass of $2\, moles$ of water $(H_2O)$ = $2 	imes 18\, g = 36\, g$. $840 = 36\, g 	imes 4.2\, J\, g^{-1}\, K^{-1} 	imes (T - 290\, K)$. $840 = 151.2 	imes (T - 290)$. $T - 290 = \frac{840}{151.2} \approx 5.55\, K$. $T = 290 + 5.55 = 295.55\, K \approx 295.6\, K$.

Similar Questions

Enthalpy of combustion of $CH_4, C_2H_6$ and $C_3H_8$ are $-210.8, -368.4$ and $-526.2 \ k \ cal \ mol^{-1}$ respectively. Enthalpy of combustion of hexane can be predicted as........$k \ cal \ mol^{-1}$

For the reaction $2Cl_{(g)} \rightarrow Cl_{2(g)}$,the signs of $\Delta H$ and $\Delta S$ are respectively:

The enthalpies of combustion of carbon and carbon monoxide are $-393.5 \, kJ \, mol^{-1}$ and $-283 \, kJ \, mol^{-1}$ respectively. The enthalpy of formation of carbon monoxide per mole is $....... \, kJ \, mol^{-1}$. (in $.5$)

If standard molar enthalpy change and standard molar internal energy change measured in a bomb calorimeter are equal,which one of the following statements is correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module