$A$ microwave of wavelength $2.0 \ cm$ falls normally on a slit of width $4.0 \ cm$. The angular spread of the central maxima of the diffraction pattern obtained on a screen $1.5 \ m$ away from the slit,will be: (in $^{\circ}$)

Consider sunlight incident on a slit of width $10^4 \ \mathring{A}$. The image seen through the slit shall

If $I_0$ is the intensity of the principal maximum in the single slit diffraction pattern,then what will be the intensity when the slit width is doubled?

If $n$ represents the order of a half-period zone,the area of this zone is approximately proportional to $n^m$,where $m$ is equal to:

In a single slit diffraction pattern,a light of wavelength $6000 \mathring A$ is used. The distance between the first and third minima in the diffraction pattern is found to be $3 \text{ mm}$ when the screen is placed $50 \text{ cm}$ away from the slit. The width of the slit is . . . . . . $\times 10^{-4} \text{ m}$.

Assertion : Diffraction takes place for all types of waves,mechanical or non-mechanical,transverse or longitudinal.
Reason : Diffraction effects are perceptible only if the wavelength of the wave is comparable to the dimensions of the diffracting device.