A motorcyclist of mass m is to negotiate a cu | vedclass

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(B) For a motorcyclist to negotiate a curve of radius $r$ with speed $v$ safely,the necessary centripetal force is provided by the static friction bet

Vedclass · Accepted Answer

$\frac{v^2}{gr}$

Vedclass · Answer

(B) For a motorcyclist to negotiate a curve of radius $r$ with speed $v$ safely,the necessary centripetal force is provided by the static friction between the tires and the road.The required centripetal force is $F_c = \frac{mv^2}{r}$.The maximum available static frictional force is $f_{max} = \mu N$,where $N = mg$ is the normal reaction.For safe negotiation,the frictional force must be at least equal to the required centripetal force:$f_{max} \geq F_c$$\mu mg \geq \frac{mv^2}{r}$$\mu \geq \frac{v^2}{rg}$Therefore,the minimum coefficient of friction is $\mu_{min} = \frac{v^2}{rg}$.

$A$ motorcyclist of mass $m$ is to negotiate a curve of radius $r$ with a speed $v$. The minimum value of the coefficient of friction so that this negotiation may take place safely,is

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