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(B) The equation of the angle bisectors of two planes $A_1x + B_1y + C_1z + D_1 = 0$ and $A_2x + B_2y + C_2z + D_2 = 0$ is given by $\frac{A_1x + B_1y

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$(2, -4, 1)$

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(B) The equation of the angle bisectors of two planes $A_1x + B_1y + C_1z + D_1 = 0$ and $A_2x + B_2y + C_2z + D_2 = 0$ is given by $\frac{A_1x + B_1y + C_1z + D_1}{\sqrt{A_1^2 + B_1^2 + C_1^2}} = \pm \frac{A_2x + B_2y + C_2z + D_2}{\sqrt{A_2^2 + B_2^2 + C_2^2}}$.For the given planes $2x - y + 2z - 4 = 0$ and $x + 2y + 2z - 2 = 0$,the equation is:$\frac{2x - y + 2z - 4}{\sqrt{2^2 + (-1)^2 + 2^2}} = \pm \frac{x + 2y + 2z - 2}{\sqrt{1^2 + 2^2 + 2^2}}$$\frac{2x - y + 2z - 4}{3} = \pm \frac{x + 2y + 2z - 2}{3}$$2x - y + 2z - 4 = \pm(x + 2y + 2z - 2)$.Case $I$ (Positive sign):$2x - y + 2z - 4 = x + 2y + 2z - 2$$x - 3y - 2 = 0$.Case $II$ (Negative sign):$2x - y + 2z - 4 = -(x + 2y + 2z - 2)$$2x - y + 2z - 4 = -x - 2y - 2z + 2$$3x + y + 4z - 6 = 0$.Checking the options for equation $3x + y + 4z - 6 = 0$:For $(2, -4, 1)$: $3(2) + (-4) + 4(1) - 6 = 6 - 4 + 4 - 6 = 0$. This satisfies the equation.

$A$ plane which bisects the angle between the two given planes $2x - y + 2z - 4 = 0$ and $x + 2y + 2z - 2 = 0$,passes through the point

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