$A$ radioactive element with half-life $6.5 \ hr$ has $48 \times 10^{19}$ atoms. Number of atoms left after $26 \ hr$ is:

  • A
    $24 \times 10^{19}$
  • B
    $12 \times 10^{19}$
  • C
    $3 \times 10^{19}$
  • D
    $6 \times 10^{19}$

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