A rectangular surface of sides 10 ,cm and 15 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electric flux $\phi$ through a surface is given by the formula $\phi = E A \cos 	heta$,where $	heta$ is the angle between the electric field

Vedclass · Accepted Answer

$0.1875$

Vedclass · Answer

(B) The electric flux $\phi$ through a surface is given by the formula $\phi = E A \cos 	heta$,where $	heta$ is the angle between the electric field vector $\vec{E}$ and the area vector $\vec{A}$.Given,the surface makes an angle of $30^{\circ}$ with the electric field. The area vector $\vec{A}$ is perpendicular to the surface. Therefore,the angle $	heta$ between the area vector $\vec{A}$ and the electric field $\vec{E}$ is $	heta = 90^{\circ} - 30^{\circ} = 60^{\circ}$.Area $A = 10 \,cm 	imes 15 \,cm = 0.1 \,m 	imes 0.15 \,m = 0.015 \,m^2$.Electric field $E = 25 \,V/m$.Flux $\phi = E A \cos 60^{\circ} = 25 	imes 0.015 	imes 0.5 = 0.1875 \,Nm^2/C$.

$A$ rectangular surface of sides $10 \,cm$ and $15 \,cm$ is placed inside a uniform electric field of $25 \,V/m$,such that the surface makes an angle of $30^{\circ}$ with the direction of the electric field. Find the flux of the electric field through the rectangular surface in $Nm^2/C$.

Similar Questions

In a certain region of space,there exists a uniform electric field of value $2 \times 10^2 \hat{k} \ Vm^{-1}$. $A$ rectangular coil of dimension $10 \ cm \times 20 \ cm$ is placed in the $xy$-plane. The electric flux through the coil is......$Vm$.

Two equations are given below:
$A. \oint E \cdot dA = \frac{Q}{\varepsilon_0}$
$B. \oint B \cdot dA = 0$
They are:

The charge distribution is shown in the figure below. The electric flux through the surface $S$ due to these charges is .........

The $S.I.$ unit of electric flux is

Consider a uniform electric field $\vec{E} = 3 \times 10^3 \hat{k} \text{ N C}^{-1}$. The electric flux of this field through a square of $20 \text{ cm}$ on a side whose plane is parallel to the $yz$-plane is $....... \text{ N m}^2 \text{ C}^{-1}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module