A single compound of the structure CH_3-CO-CH | vedclass

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Question

(A) Ozonolysis of a cyclic alkene involves the cleavage of the double bond to form a dicarbonyl compound. The given product is $CH_3-CO-CH_2-CH_2-CH_2

Vedclass · Accepted Answer

$1,1-dimethylcyclopent-1-ene$

Vedclass · Answer

(A) Ozonolysis of a cyclic alkene involves the cleavage of the double bond to form a dicarbonyl compound. The given product is $CH_3-CO-CH_2-CH_2-CH_2-CHO$. This is a $6$-carbon chain with a ketone group at position $2$ and an aldehyde group at position $6$. This implies the original cyclic compound must have been a $6$-membered ring,specifically $1-methylcyclohex-1-ene$. However,looking at the options provided,we must evaluate which cyclic compound yields this specific structure. The structure $CH_3-CO-CH_2-CH_2-CH_2-CHO$ is $6-oxohexanal$. This is formed by the oxidative cleavage of $1-methylcyclohex-1-ene$. Given the options are all $5$-membered rings,there might be a discrepancy in the question's structure. Re-evaluating the product $CH_3-CO-CH_2-CH_2-CH_2-CHO$,it corresponds to the ozonolysis of $1-methylcyclohex-1-ene$. If the question implies a $5$-membered ring,the product would be different. Based on standard chemistry problems of this type,$1-methylcyclohex-1-ene$ is the correct precursor for this specific linear dicarbonyl.

$A$ single compound of the structure $CH_3-CO-CH_2-CH_2-CH_2-CHO$ is obtainable from the ozonolysis of which of the following cyclic compounds?

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The reaction is given as:
$(CH_3)_2C=C(CH_3)_2 + (CH_3)_3N^{+}-O^{-} + H_2O \xrightarrow{OsO_4 (10^{-4} \text{ mole})} A + (CH_3)_3N$
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