$A$ solution of the equation $\tan^{-1}(1 + x) + \tan^{-1}(1 - x) = \frac{\pi}{2}$ is
- A$x = 1$
- B$x = -1$
- C$x = 0$
- D$x = \pi$
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Similar Questions
Evaluate: $\cos ^{-1}\left(\frac{4}{5}\right)+\cos ^{-1}\left(\frac{12}{13}\right)$
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View Solution$\cos \left[ 2\cos^{-1}\frac{1}{5} + \sin^{-1}\frac{1}{5} \right] = $
$\tan^{-1}\left(\frac{1}{11}\right) + \tan^{-1}\left(\frac{2}{12}\right) = $
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View SolutionThe value of $\tan \left(2 \tan ^{-1}\left(\frac{3}{5}\right)+\sin ^{-1}\left(\frac{5}{13}\right)\right)$ is equal to:
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