A straight line makes an angle of 135^circ wi | vedclass

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(C) The equation of a line in slope-intercept form is given by $y = mx + c$.Given that the line makes an angle of $	heta = 135^\circ$ with the $x$-ax

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$x + y + 5 = 0$

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(C) The equation of a line in slope-intercept form is given by $y = mx + c$.Given that the line makes an angle of $	heta = 135^\circ$ with the $x$-axis,the slope $m$ is:$m = 	an(135^\circ) = -1$.The line cuts the $y$-axis at a distance of $-5$ from the origin,so the $y$-intercept $c = -5$.Substituting these values into the slope-intercept form:$y = (-1)x + (-5)$$y = -x - 5$Rearranging the terms to the general form:$x + y + 5 = 0$.Thus,the correct option is $C$.

$A$ straight line makes an angle of $135^\circ$ with the $x$-axis and cuts the $y$-axis at a distance of $-5$ from the origin. The equation of the line is

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