$A$ straight line passes through $P(1, 2)$ such that its intercept between the axes is bisected at $P$. Its equation is:

If $(a, -2a), a > 0$ is the midpoint of a line segment intercepted between the coordinate axes,then the equation of the line is

$A$ straight line $L$ at a distance of $4$ units from the origin makes positive intercepts on the coordinate axes and the perpendicular from the origin to this line makes an angle of $60^o$ with the line $x + y = 0$. Then an equation of the line $L$ is

If the coordinates of the points $A$ and $B$ are $(3, 3)$ and $(7, 6)$,then the length of the portion of the line $AB$ intercepted between the axes is

If $x \cos \theta + y \sin \theta = p$ is the normal form and $y = mx + c$ is the slope-intercept form of the line $x + 2y + 1 = 0$,then $\tan^{-1}(\tan \theta + m + c) = $

Reduce the following equation into intercept form and find its intercepts on the axes: $4x - 3y = 6$.