A street light bulb is fixed on a pole 6 , m | vedclass

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(C) Let $A$ be the position of the street bulb fixed on a pole $AB = 6 \, m$ and $CD = 1.5 \, m$ be the height of a woman and her shadow be $ED = 3 \,

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(C) Let $A$ be the position of the street bulb fixed on a pole $AB = 6 \, m$ and $CD = 1.5 \, m$ be the height of a woman and her shadow be $ED = 3 \, m$. Let the distance between the pole and the woman be $x \, m$.Here,the woman and the pole are both standing vertically.So,$CD \parallel AB$.In $	riangle CDE$ and $	riangle ABE$,$\angle E = \angle E$ [common angle].$\angle ABE = \angle CDE = 90^{\circ}$ [each equal to $90^{\circ}$].Therefore,$	riangle CDE \sim 	riangle ABE$ [by $AAA$ similarity criterion].Then,$\frac{ED}{EB} = \frac{CD}{AB}$.$\frac{3}{3 + x} = \frac{1.5}{6}$.$3 	imes 6 = 1.5(3 + x)$.$18 = 4.5 + 1.5x$.$1.5x = 18 - 4.5$.$1.5x = 13.5$.$x = \frac{13.5}{1.5} = 9 \, m$.Hence,she is at a distance of $9 \, m$ from the base of the pole.

$A$ street light bulb is fixed on a pole $6 \, m$ above the level of the street. If a woman of height $1.5 \, m$ casts a shadow of $3 \, m$,find how far she is away from the base of the pole. (in $m$)

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