A system consists of 3 particles each of mass | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The coordinates of the centre of mass $(X_{cm}, Y_{cm})$ for a system of particles are given by:$X_{cm} = \frac{m_1 x_1 + m_2 x_2 + m_3 x_3}{m_1 +

Vedclass · Accepted Answer

$(2, 2)$

Vedclass · Answer

(C) The coordinates of the centre of mass $(X_{cm}, Y_{cm})$ for a system of particles are given by:$X_{cm} = \frac{m_1 x_1 + m_2 x_2 + m_3 x_3}{m_1 + m_2 + m_3}$$Y_{cm} = \frac{m_1 y_1 + m_2 y_2 + m_3 y_3}{m_1 + m_2 + m_3}$Given $m_1 = m_2 = m_3 = m$ and positions $(x_1, y_1) = (1, 1), (x_2, y_2) = (2, 2), (x_3, y_3) = (3, 3)$.$X_{cm} = \frac{m(1) + m(2) + m(3)}{m + m + m} = \frac{6m}{3m} = 2$$Y_{cm} = \frac{m(1) + m(2) + m(3)}{m + m + m} = \frac{6m}{3m} = 2$Thus,the centre of mass is at $(2, 2)$.

$A$ system consists of $3$ particles each of mass $m$ located at $(1, 1), (2, 2),$ and $(3, 3)$. The coordinates of the centre of mass are

Similar Questions

Three particles of mass $1 \ kg, 2 \ kg$ and $3 \ kg$ are placed at the vertices $A, B$ and $C$ respectively of an equilateral triangle $ABC$ of side $1 \ m$. The centre of mass of the system from vertex $A$ (located at origin) is

The centre of mass of a body

$A$ square plate and a circular disc of uniform density are arranged as shown in the figure. The center of mass of this combined system will be .........

Three point masses $m_1 = 1.6 \, kg$,$m_2 = 2.0 \, kg$,and $m_3 = 2.4 \, kg$ are placed at the corners of a thin massless rectangular sheet $(1.2 \, m \times 1.0 \, m)$ as shown. The center of mass will be located at the point ........... $m$.

In carbon monoxide molecules,the carbon and the oxygen atoms are separated by a distance of $1.2 \,\mathring{A}$. The distance of the centre of mass from the carbon atom is ........ $\mathring{A}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module