$A$ uniform chain of length $L$ and mass $M$ is lying on a smooth table and one-third of its length is hanging vertically down over the edge of the table. If $g$ is the acceleration due to gravity,the work required to pull the hanging part onto the table is:
- A$MgL$
- B$\frac{MgL}{3}$
- C$\frac{MgL}{9}$
- D$\frac{MgL}{18}$
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