A vessel contains 16 ,g of hydrogen and 128 , | vedclass

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(C) The molar mass of $H_{2}$ is $2 \,g/mol$. Number of moles of $H_{2} = \frac{16 \,g}{2 \,g/mol} = 8 \,moles$.The molar mass of $O_{2}$ is $32 \,g/m

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$27 	imes 10^{4}$

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(C) The molar mass of $H_{2}$ is $2 \,g/mol$. Number of moles of $H_{2} = \frac{16 \,g}{2 \,g/mol} = 8 \,moles$.The molar mass of $O_{2}$ is $32 \,g/mol$. Number of moles of $O_{2} = \frac{128 \,g}{32 \,g/mol} = 4 \,moles$.Total number of moles $n = 8 + 4 = 12 \,moles$.At $STP$,the molar volume of an ideal gas is $22.4 \,L = 22.4 	imes 10^{3} \,cm^{3}$.Total volume $V = n 	imes 22.4 	imes 10^{3} \,cm^{3} = 12 	imes 22.4 	imes 10^{3} \,cm^{3} = 268.8 	imes 10^{3} \,cm^{3} = 26.88 	imes 10^{4} \,cm^{3}$.Rounding to the nearest option,the volume is approximately $27 	imes 10^{4} \,cm^{3}$.

$A$ vessel contains $16 \,g$ of hydrogen and $128 \,g$ of oxygen at standard temperature and pressure $(STP)$. The volume of the vessel in $cm^{3}$ is:

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