According to Einstein's photoelectric equatio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Einstein's photoelectric equation is given by $K_{max} = h
u - \Phi$, where $K_{max}$ is the maximum kinetic energy of the emitted photoelectrons

Vedclass · Accepted Answer

is the same for all metals and independent of the intensity of radiation.

Vedclass · Answer

(C) Einstein's photoelectric equation is given by $K_{max} = h
u - \Phi$, where $K_{max}$ is the maximum kinetic energy of the emitted photoelectrons, $h$ is Planck's constant, $
u$ is the frequency of incident radiation, and $\Phi$ is the work function of the metal.Comparing this equation with the straight-line equation $y = mx + c$, we get $y = K_{max}$, $x = 
u$, $m = h$, and $c = -\Phi$.The slope of the graph of $K_{max}$ versus $
u$ is $h$ (Planck's constant).Since $h$ is a universal constant, the slope is the same for all metals and is independent of the intensity of the incident radiation.

According to Einstein's photoelectric equation, the graph of the kinetic energy of the emitted photoelectrons versus the frequency of incident radiation gives a straight line whose slope

Similar Questions

Work function of lithium and copper are respectively $2.3 \ eV$ and $4.0 \ eV$. Which one of the metal will be useful for the photoelectric cell working with visible light? $(h = 6.6 \times 10^{-34} \ J \cdot s, c = 3 \times 10^8 \ m/s)$

When the light source is kept $20 \ cm$ away from a photo cell,a stopping potential of $0.6 \ V$ is obtained. When the source is kept $40 \ cm$ away,the stopping potential will be .......... $V$.

The stopping potential for a photoelectric emission process is $10 \ V$. The maximum kinetic energy of the electrons ejected in the process is [Charge on electron $e = 1.6 \times 10^{-19} \ C$]

The threshold wavelength for sodium is $6 \times 10^{-7} \, m$. Photoemission occurs for light of wavelength $\lambda$ if:

Vedclass Test Series

Exam Paper Generator

Online Exam Module