Ajay and Sunil together can complete a piece | vedclass

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(B) Let the work done by Ajay,Sunil,and Sanjay in one day be $A, S,$ and $J$ respectively.Given:$A + S = 1/10$$S + J = 1/15$$J + A = 1/20$Adding these

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$10$

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(B) Let the work done by Ajay,Sunil,and Sanjay in one day be $A, S,$ and $J$ respectively.Given:$A + S = 1/10$$S + J = 1/15$$J + A = 1/20$Adding these,$2(A + S + J) = 1/10 + 1/15 + 1/20 = (6+4+3)/60 = 13/60$.So,$A + S + J = 13/120$.Work done by all three in $6$ days $= 6 	imes (13/120) = 13/20$.Remaining work $= 1 - 13/20 = 7/20$.Sunil and Sanjay work for $4$ more days. Their rate is $S + J = 1/15$.Work done by them in $4$ days $= 4 	imes (1/15) = 4/15$.Remaining work for Sanjay $= 7/20 - 4/15 = (21-16)/60 = 5/60 = 1/12$.Sanjay's individual rate $J = (A+S+J) - (A+S) = 13/120 - 1/10 = (13-12)/120 = 1/120$.Time taken by Sanjay to complete $1/12$ of the work $= (1/12) / (1/120) = 10$ days.

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