All the pairs $(x, y)$ that satisfy the inequality $2^{\sqrt{\sin^2 x - 2 \sin x + 5}} \cdot \frac{1}{4^{\sin^2 y}} \leq 1$ also satisfy the equation

  • A
    $2|\sin x| = \sin y$
  • B
    $2 \sin x = \sin y$
  • C
    $\sin x = 2 \sin y$
  • D
    $\sin x = |\sin y|$

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$(3)$ $\lim _{n \rightarrow \infty} f(n)=\frac{1}{2}$
$(4)$ If $\alpha=\tan \left(\cos ^{-1} f(6)\right)$,then $\alpha^2+2 \alpha-1=0$

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