All the values of m for which both roots of t | vedclass

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(C) Given the quadratic equation $x^2 - 2mx + m^2 - 1 = 0$.This can be rewritten as $(x - m)^2 - 1 = 0$.Factoring the expression,we get $(x - m - 1)(x

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$(-1, 3)$

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(C) Given the quadratic equation $x^2 - 2mx + m^2 - 1 = 0$.This can be rewritten as $(x - m)^2 - 1 = 0$.Factoring the expression,we get $(x - m - 1)(x - m + 1) = 0$.Thus,the roots are $x_1 = m - 1$ and $x_2 = m + 1$.We are given that both roots must satisfy the condition $-2 For the smaller root $x_1 = m - 1$,we have $m - 1 > -2$,which implies $m > -1$.For the larger root $x_2 = m + 1$,we have $m + 1 Combining these inequalities,we get $-1 Therefore,the values of $m$ lie in the interval $(-1, 3)$.

All the values of $m$ for which both roots of the equation $x^2 - 2mx + m^2 - 1 = 0$ are greater than $-2$ but less than $4$ lie in the interval

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