An alpha nucleus of energy $\frac{1}{2}mv^2$ bombards a heavy nuclear target of charge $Ze$. Then the distance of closest approach for the alpha nucleus will be proportional to

  • A
    $v^2$
  • B
    $\frac{1}{Ze}$
  • C
    $\frac{1}{m}$
  • D
    $\frac{1}{v^4}$

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