(A) The acceleration due to gravity on the surface of a planet is given by $g = \frac{GM}{R^2}$.Let $M_e$ and $R_e$ be the mass and radius of the Eart

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Both the mass and radius of the planet are half that of Earth

(A) The acceleration due to gravity on the surface of a planet is given by $g = \frac{GM}{R^2}$.Let $M_e$ and $R_e$ be the mass and radius of the Earth,and $g_e = \frac{GM_e}{R_e^2}$ be the acceleration due to gravity on Earth.For the strange planet,we are given $g_p = 2g_e$.Checking option $A$: If $M_p = \frac{M_e}{2}$ and $R_p = \frac{R_e}{2}$,then $g_p = \frac{G(M_e/2)}{(R_e/2)^2} = \frac{GM_e/2}{R_e^2/4} = 2 \frac{GM_e}{R_e^2} = 2g_e$.Thus,option $A$ is correct.

Class 11 Physics Gravitation Acceleration Due to Gravity and its Variation

Easy

An astronaut on a strange planet finds that the acceleration due to gravity is twice that on the surface of the Earth. Which of the following could explain this?

KCET 2010 All KCET

A
Both the mass and radius of the planet are half that of Earth
B
Radius of the planet is half that of Earth,but the mass is the same as that of Earth
C
Both the mass and radius of the planet are twice that of Earth
D
Mass of the planet is half that of Earth,but radius is the same as that of Earth

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Gravitation

Subtopic

Acceleration Due to Gravity and its Variation

Previous Year

KCET 2010 Paper All KCET years →

If $R$ is the radius of the earth and $g$ is the acceleration due to gravity on the earth's surface,the mean density of the earth is

Medium

View Solution

The figure shows the variation of acceleration due to gravity with distance from the center of a uniform spherical planet of radius $R$. What is $r_2 - r_1$?

Difficult

View Solution

Find the magnitude of acceleration due to gravity at a height of $10 \, km$ from the surface of the earth.

Medium

View Solution

Two bodies each of mass $m$ are hung from a balance whose scale pans differ in a vertical height by $h$. If the mean density of the earth is $\rho$,the error in weighing is

MediumAP EAMCET 2019

View Solution

The percentage decrease in the weight of a body when taken to a height of $48 \text{ km}$ above the surface of the earth is (Radius of the earth is $6400 \text{ km}$) (in $\%$)

DifficultMHT CET 2026

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

An astronaut on a strange planet finds that the acceleration due to gravity is twice that on the surface of the Earth. Which of the following could explain this?

Similar Questions

If $R$ is the radius of the earth and $g$ is the acceleration due to gravity on the earth's surface,the mean density of the earth is

The figure shows the variation of acceleration due to gravity with distance from the center of a uniform spherical planet of radius $R$. What is $r_2 - r_1$?

Find the magnitude of acceleration due to gravity at a height of $10 \, km$ from the surface of the earth.

Two bodies each of mass $m$ are hung from a balance whose scale pans differ in a vertical height by $h$. If the mean density of the earth is $\rho$,the error in weighing is

The percentage decrease in the weight of a body when taken to a height of $48 \text{ km}$ above the surface of the earth is (Radius of the earth is $6400 \text{ km}$) (in $\%$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module