An electron accelerated through a potential difference $V_1$ has a de-Broglie wavelength $\lambda$. When the potential is changed to $V_2$,its de-Broglie wavelength increases by $50 \%$. The value of $\left(\frac{V_1}{V_2}\right)$ is

  • A
    $3$:$1$
  • B
    $9$:$4$
  • C
    $3$:$2$
  • D
    $4$:$1$

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