An image is formed at a distance of 100 cm f | vedclass

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(A) The refraction formula at a spherical surface is given by:$\frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R}$Given values:$\mu_1 = 1$ (a

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$20$

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(A) The refraction formula at a spherical surface is given by:$\frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R}$Given values:$\mu_1 = 1$ (air),$\mu_2 = 1.5$ (glass)$u = -100 \ cm$ (distance of object from the surface,taken as negative by sign convention)$v = +100 \ cm$ (distance of image from the surface,taken as positive as it is formed inside the glass)Substituting these values into the formula:$\frac{1.5}{100} - \frac{1}{-100} = \frac{1.5 - 1}{R}$$\frac{1.5}{100} + \frac{1}{100} = \frac{0.5}{R}$$\frac{2.5}{100} = \frac{0.5}{R}$$R = \frac{0.5 	imes 100}{2.5} = \frac{50}{2.5} = 20 \ cm$Thus,the radius of curvature is $20 \ cm$.

An image is formed at a distance of $100 \ cm$ from the glass surface when light from a point source in air falls on a spherical glass surface with a refractive index of $1.5$. The distance of the light source from the glass surface is $100 \ cm$. The radius of curvature is (in $cm$)

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