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(A) The potential energy $(PE)$ of an object at a height $(h)$ is given by the formula: $PE = m \cdot g \cdot h$,where $m$ is the mass,$g$ is the acce

Vedclass · Accepted Answer

$250\,J$

Vedclass · Answer

(A) The potential energy $(PE)$ of an object at a height $(h)$ is given by the formula: $PE = m \cdot g \cdot h$,where $m$ is the mass,$g$ is the acceleration due to gravity,and $h$ is the height.Given: Mass $(m)$ = $5\,kg$,Height $(h)$ = $5\,m$,Acceleration due to gravity $(g)$ $\approx 10\,m/s^2$.The loss of potential energy as the object falls to the ground is equal to the initial potential energy at height $h$.$PE = 5\,kg 	imes 10\,m/s^2 	imes 5\,m = 250\,J$.Therefore,the loss of potential energy is $250\,J$.

An object of mass $5\,kg$ falls from a height of $5\,m$ above the ground. The loss of potential energy of the mass is:

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