(D) The resonant angular frequency of a series $LCR$ circuit is given by $\omega_{R} = \frac{1}{\sqrt{LC}}$.From the given diagrams,the time period $T

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current will lead source voltage after replacing the source

(D) The resonant angular frequency of a series $LCR$ circuit is given by $\omega_{R} = \frac{1}{\sqrt{LC}}$.From the given diagrams,the time period $T$ of the emf in diagram $-2$ is greater than that in diagram $-1$ $(T_2 > T_1)$. Since angular frequency $\omega = \frac{2\pi}{T}$,it follows that $\omega_2 When the operating frequency $\omega$ is less than the resonant frequency $\omega_R$,the capacitive reactance $X_C = \frac{1}{\omega C}$ is greater than the inductive reactance $X_L = \omega L$.Therefore,the circuit behaves as a capacitive circuit,and the current leads the source voltage.

Class 12 Physics Alternating Current Half Power Frequency , Quality Factor ,Resonance in AC Circuit

Medium

$A$ series $LCR$ circuit is resonating with a source whose emf varies with time as described in diagram $-1$. If we replace the source by another source whose emf varies with time according to diagram $-2$,then:

A
for getting resonance again,decrease $R$
B
current will remain in phase with source voltage
C
for getting resonance again,decrease $C$
D
current will lead source voltage after replacing the source

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Alternating Current

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Half Power Frequency , Quality Factor ,Resonance in AC Circuit

$A$ series $LCR$ circuit with inductance $L = 10\,H$,capacitance $C = 10\,\mu F$,and resistance $R = 50\,\Omega$ is connected to an $AC$ source of voltage $V = 200 \sin(100t)\,V$. If the resonant frequency of the $LCR$ circuit is $\nu_{0}$ and the frequency of the $AC$ source is $\nu$,then:

MediumNEET 2022

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For a given series $LCR$ circuit,it is found that maximum current is drawn when the value of the variable capacitance is $2.5 \ nF$. If a resistance of $200 \ \Omega$ and a $100 \ mH$ inductor are being used in the given circuit,the frequency of the $AC$ source is $... \times 10^3 \ Hz$. (Given $\pi^2 = 10$)

DifficultJEE MAIN 2024

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In a series $LCR$ resonant circuit, $R = 800 \text{ } \Omega$, $C = 2 \text{ } \mu\text{F}$ and the voltage across the resistance is $200 \text{ V}$. The angular frequency is $\omega = 250 \text{ rad/s}$. At resonance, what is the voltage across the capacitance (in $\text{ V}$)?

DifficultMHT CET 2026

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$A$ series $LCR$ circuit with resistance $R=500 \ \Omega$ is connected to an a.c. source of $250 \ V$. When only the capacitance is removed,the current lags behind the voltage by $60^{\circ}$. When only the inductance is removed,the current leads the voltage by $60^{\circ}$. The impedance of the circuit is

MediumMHT CET 2021

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In the circuit shown in the figure, the ratio of the quality factor $(Q)$ to the bandwidth $(\Delta \omega)$ is $.............$ s.

MediumJEE MAIN 2023

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$A$ series $LCR$ circuit is resonating with a source whose emf varies with time as described in diagram $-1$. If we replace the source by another source whose emf varies with time according to diagram $-2$,then:

Similar Questions

$A$ series $LCR$ circuit with inductance $L = 10\,H$,capacitance $C = 10\,\mu F$,and resistance $R = 50\,\Omega$ is connected to an $AC$ source of voltage $V = 200 \sin(100t)\,V$. If the resonant frequency of the $LCR$ circuit is $\nu_{0}$ and the frequency of the $AC$ source is $\nu$,then:

In a series $LCR$ resonant circuit, $R = 800 \text{ } \Omega$, $C = 2 \text{ } \mu\text{F}$ and the voltage across the resistance is $200 \text{ V}$. The angular frequency is $\omega = 250 \text{ rad/s}$. At resonance, what is the voltage across the capacitance (in $\text{ V}$)?

In the circuit shown in the figure, the ratio of the quality factor $(Q)$ to the bandwidth $(\Delta \omega)$ is $.............$ s.

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