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(B) For maximum current,the circuit must be in resonance.The resonant frequency is given by the formula:$f_0 = \frac{1}{2 \pi \sqrt{L 	imes C}}$Given

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$10$

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(B) For maximum current,the circuit must be in resonance.The resonant frequency is given by the formula:$f_0 = \frac{1}{2 \pi \sqrt{L 	imes C}}$Given values:$L = 100 \ mH = 100 	imes 10^{-3} \ H = 0.1 \ H$$C = 2.5 \ nF = 2.5 	imes 10^{-9} \ F$Substituting the values into the formula:$f_0 = \frac{1}{2 \pi \sqrt{0.1 	imes 2.5 	imes 10^{-9}}}$$f_0 = \frac{1}{2 \pi \sqrt{25 	imes 10^{-11}}}$$f_0 = \frac{1}{2 \pi \sqrt{2.5 	imes 10^{-10}}}$$f_0 = \frac{1}{2 \pi 	imes 5 	imes 10^{-5}}$Since $\pi^2 = 10$,we have $\pi = \sqrt{10} \approx 3.162$.$f_0 = \frac{1}{2 	imes \sqrt{10} 	imes 5 	imes 10^{-5}} = \frac{1}{10 \sqrt{10} 	imes 10^{-5}} = \frac{10^4}{\sqrt{10}} = \frac{10^4 	imes \sqrt{10}}{10} = 10^3 	imes \sqrt{10} \ Hz$.Wait,let's re-calculate:$f_0 = \frac{1}{2 \pi \sqrt{0.1 	imes 2.5 	imes 10^{-9}}} = \frac{1}{2 \pi \sqrt{2.5 	imes 10^{-10}}} = \frac{1}{2 \pi 	imes 1.581 	imes 10^{-5}} \approx 10000 \ Hz = 10 	imes 10^3 \ Hz$.

List-$I$	List-$II$
$(a)$ $\omega L > \frac{1}{\omega C}$	$(i)$ Current is in phase with $emf$
$(b)$ $\omega L = \frac{1}{\omega C}$	$(ii)$ Current lags behind the applied $emf$
$(c)$ $\omega L < \frac{1}{\omega C}$	$(iii)$ Maximum current occurs
$(d)$ Resonant frequency	$(iv)$ Current leads the $emf$

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