As shown in the figure,if a capacitor C is ch | vedclass

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(B) When a capacitor $C$ is charged by a battery of voltage $V$ through a resistance $R$,the total charge that flows from the battery is $Q = CV$.The

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More than $\frac{1}{2}CV^2$

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(B) When a capacitor $C$ is charged by a battery of voltage $V$ through a resistance $R$,the total charge that flows from the battery is $Q = CV$.The total work done by the battery is $W = QV = (CV)V = CV^2$.The energy stored in the capacitor is $U = \frac{1}{2}CV^2$.Since the energy supplied by the battery is $CV^2$ and the energy stored in the capacitor is $\frac{1}{2}CV^2$,the remaining energy $\frac{1}{2}CV^2$ is dissipated as heat in the resistance $R$.Therefore,the energy supplied by the battery is $CV^2$,which is more than the energy stored in the capacitor,$\frac{1}{2}CV^2$.

As shown in the figure,if a capacitor $C$ is charged by connecting it with a battery of voltage $V$ through a resistance $R$,then the energy supplied by the battery will be:

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