As shown in the figure,a force F is applied o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The forces acting on the block are: $1$. Weight $mg$ acting downwards.$2$. Applied force $F$ at an angle of $60^{\circ}$ with the horizontal,actin

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(D) The forces acting on the block are: $1$. Weight $mg$ acting downwards.$2$. Applied force $F$ at an angle of $60^{\circ}$ with the horizontal,acting downwards.$3$. Normal reaction $N$ acting upwards.$4$. Frictional force $f$ acting horizontally.Resolving the force $F$ into components:Horizontal component: $F \cos 60^{\circ} = \frac{F}{2}$Vertical component: $F \sin 60^{\circ} = \frac{F \sqrt{3}}{2}$For vertical equilibrium:$N = mg + F \sin 60^{\circ} = \sqrt{3} 	imes 10 + \frac{F \sqrt{3}}{2} = 10\sqrt{3} + \frac{F \sqrt{3}}{2}$The limiting friction is $f_{max} = \mu N = \frac{1}{2\sqrt{3}} 	imes (10\sqrt{3} + \frac{F \sqrt{3}}{2}) = 5 + \frac{F}{4}$For the block not to move,the horizontal component of the applied force must be less than or equal to the limiting friction:$F \cos 60^{\circ} \le f_{max}$$\frac{F}{2} \le 5 + \frac{F}{4}$$\frac{F}{2} - \frac{F}{4} \le 5$$\frac{F}{4} \le 5$$F \le 20 \ N$Thus,the maximum value of $F$ for the block not to move is $20 \ N$.

Similar Questions

To avoid slipping while walking on ice,one should take smaller steps because of the

$A$ block of mass $m$ lying on a rough horizontal plane is acted upon by a horizontal force $P$ and another force $Q$ inclined at an angle $\theta$ to the vertical. The minimum value of the coefficient of friction between the block and the surface for which the block will remain in equilibrium is

The maximum value of static friction is called:

The limiting value of static friction between two contact surfaces is ...........

$A$ force of $98 \, N$ is required to just start moving a body of mass $100 \, kg$ over ice. The coefficient of static friction is

Vedclass Test Series

Exam Paper Generator

Online Exam Module