Assume that light of wavelength 6000,mathring | vedclass

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(B) The limit of resolution of a telescope is given by the formula $\Delta 	heta = \frac{1.22 \lambda}{D}$,where $\lambda$ is the wavelength of light

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$2.9 	imes 10^{-7} \,	ext{radians}$

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(B) The limit of resolution of a telescope is given by the formula $\Delta 	heta = \frac{1.22 \lambda}{D}$,where $\lambda$ is the wavelength of light and $D$ is the diameter of the objective lens.Given:$\lambda = 6000\,\mathring{A} = 6000 	imes 10^{-10}\,	ext{m} = 6 	imes 10^{-7}\,	ext{m}$.$D = 100\,	ext{inch} = 100 	imes 2.54 	imes 10^{-2}\,	ext{m} = 2.54\,	ext{m}$.Substituting these values into the formula:$\Delta 	heta = \frac{1.22 	imes 6 	imes 10^{-7}}{2.54} \approx 2.88 	imes 10^{-7}\,	ext{radians}$.Rounding to the nearest provided option,we get $\Delta 	heta \approx 2.9 	imes 10^{-7}\,	ext{radians}$.

Assume that light of wavelength $6000\,\mathring{A}$ is coming from a star. What is the limit of resolution of a telescope whose objective has a diameter of $100\,\text{inch}$?

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In an optical instrument- microscope, the wavelengths of light used are $\lambda_1 = 6800 \text{ Å}$ and $\lambda_2 = 5100 \text{ Å}$. The ratio of the resolving power of the microscope corresponding to $\lambda_1$ to that for $\lambda_2$ is

Wavelengths of light used in an optical instrument are $\lambda_1 = 4000 \; \mathring{A}$ and $\lambda_2 = 5000 \; \mathring{A}$. The ratio of their respective resolving powers (corresponding to $\lambda_1$ and $\lambda_2$) is:

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Reason $(R):$ The resolving power of a telescope is given by $\frac{a}{1.22 \lambda}$.

Two points separated by a distance of $0.1\,mm$ can just be resolved in a microscope when a light of wavelength $6000\ \mathring{A}$ is used. If the light of wavelength $4800\ \mathring{A}$ is used,this limit of resolution becomes.......$mm$.

$A$ telescope uses light having a wavelength of $5000 \, \mathring{A}$ and lenses with focal lengths of $2.5 \, \text{cm}$ and $30 \, \text{cm}$. If the diameter of the aperture of the objective is $10 \, \text{cm}$,what are the resolving limit and the magnifying power of the telescope,respectively?

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