At 100, ^circ C,copper (Cu) has FCC unit cell | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The density $(d)$ of a unit cell is given by the formula: $d = \frac{Z 	imes M}{N_A 	imes a^3}$For an $FCC$ unit cell,the number of atoms per un

Vedclass · Accepted Answer

$\frac{422}{x^3}$

Vedclass · Answer

(D) The density $(d)$ of a unit cell is given by the formula: $d = \frac{Z 	imes M}{N_A 	imes a^3}$For an $FCC$ unit cell,the number of atoms per unit cell $(Z) = 4$.The atomic mass of $Cu$ $(M) = 63.55\, g\, mol^{-1}$.The Avogadro constant $(N_A) = 6.023 	imes 10^{23}\, mol^{-1}$.The edge length $(a) = x\, \mathring{A} = x 	imes 10^{-8}\, cm$.Substituting these values into the formula:$d = \frac{4 	imes 63.55}{(6.023 	imes 10^{23}) 	imes (x 	imes 10^{-8})^3}$$d = \frac{254.2}{6.023 	imes 10^{23} 	imes x^3 	imes 10^{-24}}$$d = \frac{254.2}{0.6023 	imes x^3} \approx \frac{422}{x^3}\, g\, cm^{-3}$

At $100\, ^\circ C$,copper $(Cu)$ has $FCC$ unit cell structure with cell edge length $x\, \mathring{A}$. What is the approximate density of $Cu$ (in $g\, cm^{-3}$) at this temperature? [Atomic mass of $Cu = 63.55\, u$]

Similar Questions

The number of atoms in $4.5 \ g$ of a face-centred cubic crystal with edge length $300 \ pm$ is (Given: Density $= 10 \ g \ cm^{-3}$ and $N_A = 6.022 \times 10^{23}$)

$A$ compound can crystallise in two forms $\alpha$ and $\beta$ which are $fcc$ and $bcc$, respectively. The $\alpha$-form has a side length of $2 \ pm$ and the $\beta$-form has a side length of $4 \ pm$. The ratio of their density $\frac{\rho_\alpha}{\rho_\beta}$ is

An element (atomic mass $100 \ g/mol$) having $bcc$ structure has unit cell edge $400 \ pm$. Then density of the element is (in $g/cm^3$)

If the edge length of a cubic unit cell in a $bcc$ structure is $400 \, pm$, then the atomic radius of the metal will be ........... $pm$.

In an $fcc$ lattice,the edge length of a silver unit cell is $4.077 \times 10^{-8} \ cm$ and the density is $10.5 \ g \ cm^{-3}$. Calculate the atomic mass of silver.

Vedclass Test Series

Exam Paper Generator

Online Exam Module