At low temperature,phenol reacts with Br_2 in | vedclass

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(B) When phenol reacts with $Br_2$ in a non-polar solvent like $CS_2$ at low temperature,the ionization of phenol is suppressed. The benzene ring is o

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$o$- and $p$-bromophenol

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(B) When phenol reacts with $Br_2$ in a non-polar solvent like $CS_2$ at low temperature,the ionization of phenol is suppressed. The benzene ring is only slightly activated,leading to mono-substitution,which yields a mixture of $o$-bromophenol and $p$-bromophenol.In contrast,when phenol reacts with $Br_2$ water,it ionizes to form the phenoxide ion. The negative charge on the oxygen atom strongly activates the benzene ring,resulting in the formation of $2, 4, 6$-tribromophenol.

At low temperature,phenol reacts with $Br_2$ in $CS_2$ to form:

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