The ratio of the number of oxygen atoms to br | vedclass

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(D) $1$. Phenetole $(C_6H_5OC_2H_5)$ undergoes nitration with $HNO_3$ and $H_2SO_4$ to form $p$-nitrophenetole as the major product $(P)$.$2$. $p$-Nit

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(D) $1$. Phenetole $(C_6H_5OC_2H_5)$ undergoes nitration with $HNO_3$ and $H_2SO_4$ to form $p$-nitrophenetole as the major product $(P)$.$2$. $p$-Nitrophenetole then undergoes bromination with $Br_2$ in the presence of $Fe$ to form $2,6$-dibromo-$4$-nitrophenetole as the major product $(Q)$.$3$. The molecular formula of $Q$ is $C_8H_7Br_2NO_3$.$4$. In $Q$,the number of oxygen atoms is $3$ and the number of bromine atoms is $2$.$5$. The ratio of oxygen atoms to bromine atoms is $\frac{3}{2} = 1.5$.$6$. Expressing $1.5$ as $.... 	imes 10^{-1}$,we get $15 	imes 10^{-1}$.$7$. Therefore,the correct option is $D$.

The ratio of the number of oxygen atoms to bromine atoms in the product $Q$ is $.... \times 10^{-1}$.

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