By Remainder Theorem,find the remainder when | vedclass

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(B) According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Given $g(x) = x + 1$,we set $g(x) = 0$ t

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$0$

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(B) According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Given $g(x) = x + 1$,we set $g(x) = 0$ to find the value of $x$:$x + 1 = 0 \Rightarrow x = -1$.Now,substitute $x = -1$ into $p(x)$:$p(-1) = (-1)^{3} - 2(-1)^{2} - 4(-1) - 1$$p(-1) = -1 - 2(1) + 4 - 1$$p(-1) = -1 - 2 + 4 - 1$$p(-1) = -4 + 4 = 0$.Therefore,the remainder is $0$.

By Remainder Theorem,find the remainder when $p(x)$ is divided by $g(x)$,where $p(x) = x^{3} - 2x^{2} - 4x - 1$ and $g(x) = x + 1$.

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