Factorise the following quadratic polynomial | vedclass

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Question

(A) To factorise $6x^2 + 19x + 10$ by splitting the middle term,we need to find two numbers whose product is $6 	imes 10 = 60$ and whose sum is $19$.

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$ (2x + 5)(3x + 2) $

Vedclass · Answer

(A) To factorise $6x^2 + 19x + 10$ by splitting the middle term,we need to find two numbers whose product is $6 	imes 10 = 60$ and whose sum is $19$.These two numbers are $15$ and $4$,since $15 	imes 4 = 60$ and $15 + 4 = 19$.Now,rewrite the middle term $19x$ as $15x + 4x$:$6x^2 + 15x + 4x + 10$Group the terms to factor out common factors:$(6x^2 + 15x) + (4x + 10)$$3x(2x + 5) + 2(2x + 5)$Finally,factor out the common binomial $(2x + 5)$:$(2x + 5)(3x + 2)$

Factorise the following quadratic polynomial by splitting the middle term:
$6x^2 + 19x + 10$

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Factorise the following quadratic polynomial by splitting the middle term:$6x^2 + 19x + 10$