Charges of $2Q$ and $-Q$ are placed on two plates of a parallel plate capacitor. If the capacitance of the capacitor is $C$,the potential difference between the plates is:
- A$V = \frac{Q}{C}$
- B$V = \frac{3Q}{2C}$
- C$V = \frac{2Q}{3C}$
- DNone of these
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