Check whether (1, 1) is a solution of the equ | vedclass

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Question

(B) Given equation is $x - 2y = 4$.For the point $(1, 1)$,we have $x = 1$ and $y = 1$.Substitute these values into the left-hand side ($L$.$H$.$S$.) o

Vedclass · Accepted Answer

No,it is not a solution.

Vedclass · Answer

(B) Given equation is $x - 2y = 4$.For the point $(1, 1)$,we have $x = 1$ and $y = 1$.Substitute these values into the left-hand side ($L$.$H$.$S$.) of the equation:$L$.$H$.$S$. $= x - 2y = 1 - 2(1) = 1 - 2 = -1$.The right-hand side ($R$.$H$.$S$.) of the equation is $4$.Since $L$.$H$.$S$. $
eq$ $R$.$H$.$S$. $(-1 
eq 4)$,the point $(1, 1)$ is not a solution of the equation $x - 2y = 4$.

Check whether $(1, 1)$ is a solution of the equation $x - 2y = 4$.

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