Consider an infinite ladder network shown in the figure. $V$ voltage $V$ is applied between the points $A$ and $B$. This applied voltage is halved after each section.

  • A
    $R_1/R_2 = 1$
  • B
    $R_1/R_2 = 1/2$
  • C
    $R_1/R_2 = 2$
  • D
    $R_1/R_2 = 3$

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$A$ circuit is comprised of eight identical batteries and a resistor $R = 0.8\,\Omega$. Each battery has an $emf$ of $1.0\, V$ and internal resistance of $0.2\,\Omega$. The voltage difference across any of the batteries is ............. $V$.

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In the given circuit diagram,the current through the battery and the charge on the capacitor,respectively,in the steady state are:

In the adjacent circuit,a voltmeter of internal resistance $R$,when connected across $B$ and $C$,reads $\frac{100}{3} \text{ V}$. Neglecting the internal resistance of the battery,the value of $R$ is:

For what value of resistance $R$ in the given circuit will the galvanometer reading be zero (in $\Omega$)? The internal resistance of both batteries is negligible.

Assertion : In a simple battery circuit,the point of the lowest potential is the negative terminal of the battery.
Reason : The current flows towards the point of the higher potential,as it does in such a circuit from the negative to the positive terminal.

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