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(D) The acceleration due to gravity $(g)$ at a height $(h)$ above the Earth's surface is given by $g_h = g(1 - 2h/R)$,where $R$ is the radius of the E

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each goes on decreasing

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(D) The acceleration due to gravity $(g)$ at a height $(h)$ above the Earth's surface is given by $g_h = g(1 - 2h/R)$,where $R$ is the radius of the Earth. As $h$ increases,$g_h$ decreases.Similarly,the acceleration due to gravity at a depth $(d)$ below the Earth's surface is given by $g_d = g(1 - d/R)$. As $d$ increases,$g_d$ decreases.Therefore,for both scientist $A$ (moving deep into a mine) and scientist $B$ (moving high up in a balloon),the measured acceleration due to gravity decreases.

Consider Earth to be a homogeneous sphere. Scientist $A$ goes deep down in a mine and scientist $B$ goes high up in a balloon. The acceleration due to gravity as measured by:

Similar Questions

The value of $g$ on the earth's surface is $9.8 \, m s^{-2}$. Suppose the earth suddenly shrinks to one-third of its present size without losing any mass. What is the value of $g$ on the surface of the shrunk earth (in $, m s^{-2}$)?

State Newton's universal law of gravitation and write an expression for it. Also,show that the acceleration due to gravity of an object is independent of its mass.

Give reasons:
$(i)$ What is meant by acceleration due to gravity?
$(ii)$ The value of $g$ is not constant on the surface of the Earth.
$(iii)$ Objects of different masses take the same time to fall from a fixed height.
$(iv)$ $G$ is known as the universal gravitational constant. Write its $SI$ unit.

Why is the value of $g$ more at the poles than at the equator?

Two objects of different masses falling freely near the surface of the moon would:

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