Why is the value of g more at the poles than | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The acceleration due to gravity is given by the formula $g = \frac{GM}{R^2}$,where $G$ is the gravitational constant,$M$ is the mass of the Earth,

Vedclass · Accepted Answer

The Earth is flattened at the poles and bulges at the equator.

Vedclass · Answer

(B) The acceleration due to gravity is given by the formula $g = \frac{GM}{R^2}$,where $G$ is the gravitational constant,$M$ is the mass of the Earth,and $R$ is the distance from the center of the Earth.Since the Earth is not a perfect sphere but is flattened at the poles and bulges at the equator,the radius $R$ at the poles is less than the radius $R$ at the equator.Because $g$ is inversely proportional to the square of the radius $(g \propto \frac{1}{R^2})$,a smaller radius at the poles results in a higher value of $g$ compared to the equator.

Why is the value of $g$ more at the poles than at the equator?

Similar Questions

Why is the value of $g$ greater at the poles than at the equator?

$A$ stone is dropped from the edge of a roof.
$(a)$ How long does it take to fall $4.9 \, m$?
$(b)$ How fast does it move at the end of that fall?
$(c)$ How fast does it move at the end of $7.9 \, m$?
$(d)$ What is its acceleration after $1 \, s$ and after $2 \, s$?

On the Earth,a stone is thrown from a height in a direction parallel to the Earth's surface,while another stone is simultaneously dropped from the same height. Which stone would reach the ground first and why?

Gravitational force acts on all objects in proportion to their masses. Why then,a heavy object does not fall faster than a light object?

Two bodies,one held $1 \, m$ vertically above the other,are released simultaneously and fall freely under gravity. After $2 \, s$,the relative separation of the bodies will be: (in $, m$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module