Consider the following reaction:2 HSO_{4}^{-} | vedclass

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(C) The reaction describes the industrial preparation of hydrogen peroxide $(H_{2}O_{2})$ via the electrolysis of ammonium or potassium hydrogen sulfa

Vedclass · Accepted Answer

$90.2$

Vedclass · Answer

(C) The reaction describes the industrial preparation of hydrogen peroxide $(H_{2}O_{2})$ via the electrolysis of ammonium or potassium hydrogen sulfate.The overall reaction is:$2 HSO_{4}^{-}(aq)$ $\xrightarrow[	ext{(2) Hydrolysis}]{	ext{(1) Electrolysis}} 2 HSO_{4}^{-}(aq) + 2 H^{+}(aq) + H_{2}O_{2}(aq)$Thus,product $A$ is hydrogen peroxide $(H_{2}O_{2})$.In the solid phase at $110 \ K$,the dihedral angle of $H_{2}O_{2}$ is $90.2^{\circ}$ due to the open book structure,whereas in the gas phase,it is $111.5^{\circ}$.

Consider the following reaction:
$2 HSO_{4}^{-}(aq)$ $\xrightarrow[\text{(2) Hydrolysis}]{\text{(1) Electrolysis}} H_{2}S_{2}O_{8}(aq)$ $\xrightarrow{\text{Hydrolysis}} 2 HSO_{4}^{-}(aq) + 2 H^{+}(aq) + A(aq)$
The dihedral angle in product $A$ in its solid phase at $110 \ K$ is ....$^{\circ}$

Similar Questions

In which of the following reactions does $H_2O_2$ act as a reducing agent?
$(I)$ $H_2O_2 + 2H^{+} + 2e^- \to 2H_2O$
$(II)$ $H_2O_2 \to O_2 + 2H^{+} + 2e^-$
$(III)$ $H_2O_2 + 2e^- \to 2OH^{-}$
$(IV)$ $H_2O_2 + 2OH^{-} \to O_2 + 2H_2O + 2e^-$

Which of the following products are formed on the hydrolysis of $NaO_2$?

The $\% \left(\frac{W}{V}\right)$ of $H_2O_2$ in $1.5 \ N$ solution is

$A$ commercial sample of $H_2O_2$ marked as $100$ volume hydrogen peroxide means:

$A$ given sample of $H_2O_2$ solution has a volume of $100 \, cm^3$. It produces $1000 \, cm^3$ of $O_2$ gas at $STP$. What is the volume strength of the given $H_2O_2$ sample?

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Consider the following reaction:$2 HSO_{4}^{-}(aq)$ $\xrightarrow[\text{(2) Hydrolysis}]{\text{(1) Electrolysis}} H_{2}S_{2}O_{8}(aq)$ $\xrightarrow{\text{Hydrolysis}} 2 HSO_{4}^{-}(aq) + 2 H^{+}(aq) + A(aq)$The dihedral angle in product $A$ in its solid phase at $110 \ K$ is ....$^{\circ}$