Consider the following sequence of reactions to give the major product $(X)$: $(i)$ $CH_3Cl$ / anhydrous $AlCl_3$, (ii) $Cl_2$ / $FeCl_3$, (iii) $K_2Cr_2O_7$ / $H_2SO_4$. $P$ g of the major product $(X)$ formed is reacted with $NaHCO_3$ solution to liberate a gas which occupied $11.2 \ dm^3$ at $STP$. $P = \text{ . . . . . . }$ g.

What are $\underline{A}, \underline{B}, \underline{C}$ in the following reactions?
$(I)$ $(CH_3 CO_2)_2 Ca \stackrel{\Delta}{\longrightarrow} \underline{A}$
$(II)$ $CH_3 CO_2 H \underset{\text{Red P}}{\stackrel{HI}{\longrightarrow}} \underline{B}$
$(III)$ $2 CH_3 CO_2 H \stackrel{P_4 O_{10}}{\longrightarrow} \underline{C}$
$\underline{A} \quad \underline{B} \quad \underline{C}$

The general formula for monocarboxylic acids is

The end product of the above reaction is:

The product $(X)$ of the reaction is:

Consider the following reaction:
$\text{Propanal} + \text{Methanal}$ $\xrightarrow[\text{(ii)}\Delta, \text{(iii)}\text{NaCN}, \text{(iv)}\text{H}_3\text{O}^+]{\text{(i)}\text{dil. NaOH}} \text{Product } B (C_5H_8O_3)$
The correct statement for product $B$ is: