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Question

(A) Let the complex number be $z = i = 0 + 1i$.The polar form is given by $z = r(\cos 	heta + i \sin 	heta)$,where $r \cos 	heta = 0$ and $r \sin \

Vedclass · Accepted Answer

$\cos \frac{\pi}{2} + i \sin \frac{\pi}{2}$

Vedclass · Answer

(A) Let the complex number be $z = i = 0 + 1i$.The polar form is given by $z = r(\cos 	heta + i \sin 	heta)$,where $r \cos 	heta = 0$ and $r \sin 	heta = 1$.Squaring and adding both equations:$r^2(\cos^2 	heta + \sin^2 	heta) = 0^2 + 1^2$$r^2(1) = 1$$r = 1$ (since $r > 0$).Now,$\cos 	heta = 0$ and $\sin 	heta = 1$.This implies $	heta = \frac{\pi}{2}$.Therefore,the polar form is $1(\cos \frac{\pi}{2} + i \sin \frac{\pi}{2}) = \cos \frac{\pi}{2} + i \sin \frac{\pi}{2}$.

Convert the given complex number in polar form: $i$

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