The argument of $\frac{1+i \sqrt{3}}{\sqrt{3}+i}$,where $i=\sqrt{-1}$,is

  • A
    $\frac{\pi}{3}$
  • B
    $\frac{\pi}{4}$
  • C
    $\frac{\pi}{6}$
  • D
    $\frac{\pi}{2}$

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