Determine p such that the equation x^{2}+5px+ | vedclass

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(B) The given quadratic equation is $x^{2}+5px+16=0$. Comparing this with the standard form $ax^{2}+bx+c=0$,we get $a=1$,$b=5p$,and $c=16$. For the qu

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$-\frac{8}{5} < p < \frac{8}{5}$

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(B) The given quadratic equation is $x^{2}+5px+16=0$. Comparing this with the standard form $ax^{2}+bx+c=0$,we get $a=1$,$b=5p$,and $c=16$. For the quadratic equation to have no real roots,the discriminant $D$ must be less than $0$. $D = b^{2}-4ac Substituting the values,we get $(5p)^{2}-4(1)(16) $25p^{2}-64 $25p^{2} $p^{2} Taking the square root on both sides,we get $|p| This implies $-\frac{8}{5} < p < \frac{8}{5}$.

Determine $p$ such that the equation $x^{2}+5px+16=0$ has no real roots.

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