The end points of the diameter of a circle ar | vedclass

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(B) The diameter of the circle is the distance between the points $(2, 4)$ and $(2, 6)$.Using the distance formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y

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$1$

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(B) The diameter of the circle is the distance between the points $(2, 4)$ and $(2, 6)$.Using the distance formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$, we get:Diameter $= \sqrt{(2 - 2)^2 + (6 - 4)^2} = \sqrt{0^2 + 2^2} = \sqrt{4} = 2$.The radius $r$ is half of the diameter.$r = \frac{	ext{Diameter}}{2} = \frac{2}{2} = 1$.Therefore, the radius of the circle is $1$.

The end points of the diameter of a circle are $(2, 4)$ and $(2, 6)$. The radius of the circle is:

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