Energy required to dissociate 16 g of oxygen | vedclass

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Question

(B) The molar mass of oxygen gas $(O_2)$ is $32 \ g \ mol^{-1}$.Given mass of $O_2 = 16 \ g$.Number of moles of $O_2 = \frac{16 \ g}{32 \ g \ mol^{-1}

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$2x \ kJ \ mol^{-1}$

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(B) The molar mass of oxygen gas $(O_2)$ is $32 \ g \ mol^{-1}$.Given mass of $O_2 = 16 \ g$.Number of moles of $O_2 = \frac{16 \ g}{32 \ g \ mol^{-1}} = 0.5 \ mol$.Energy required to dissociate $0.5 \ mol$ of $O_2$ is $x \ kJ$.Heat of atomisation is defined as the energy required to produce $1 \ mol$ of gaseous atoms from $1 \ mol$ of the substance.The dissociation reaction is: $O_2(g) \rightarrow 2O(g)$.Since $0.5 \ mol$ of $O_2$ requires $x \ kJ$,then $1 \ mol$ of $O_2$ requires $2x \ kJ$.Thus,the heat of atomisation for $1 \ mol$ of $O_2$ is $2x \ kJ \ mol^{-1}$.

Energy required to dissociate $16 \ g$ of oxygen gas $(O_2)$ into free atoms is $x \ kJ$. The heat of atomisation of oxygen is:

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