કિંમત શોધો: sqrt{sin ^4 x+4 cos ^2 x}-sqrt{co | vedclass

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(D) આપેલ પદાવલિ: $\sqrt{\sin ^4 x+4 \cos ^2 x}-\sqrt{\cos ^4 x+4 \sin ^2 x}$ નિત્યસમ $\cos ^2 x = 1-\sin ^2 x$ અને $\sin ^2 x = 1-\cos ^2 x$ નો ઉપયોગ

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$\cos 2 x$

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(D) આપેલ પદાવલિ: $\sqrt{\sin ^4 x+4 \cos ^2 x}-\sqrt{\cos ^4 x+4 \sin ^2 x}$ નિત્યસમ $\cos ^2 x = 1-\sin ^2 x$ અને $\sin ^2 x = 1-\cos ^2 x$ નો ઉપયોગ કરતા: $= \sqrt{\sin ^4 x-4 \sin ^2 x+4}-\sqrt{\cos ^4 x-4 \cos ^2 x+4}$ $= \sqrt{(\sin ^2 x-2)^2}-\sqrt{(\cos ^2 x-2)^2}$ $= |\sin ^2 x-2|-|\cos ^2 x-2|$ $= (2-\sin ^2 x)-(2-\cos ^2 x)$ $= \cos ^2 x-\sin ^2 x$ $= \cos 2 x$

કિંમત શોધો: $\sqrt{\sin ^4 x+4 \cos ^2 x}-\sqrt{\cos ^4 x+4 \sin ^2 x}$

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