Express the following linear equation in the form $ax + by + c = 0$ and indicate the values of $a, b,$ and $c$ in each case:
$\pi x - 3y = 18$
$\pi x - 3y = 18$
(N/A) To express the equation in the form $ax + by + c = 0$,we subtract $18$ from both sides:
$\pi x - 3y - 18 = 0$
Comparing this with the standard form $ax + by + c = 0$,we get:
$a = \pi$
$b = -3$
$c = -18$
$\pi x - 3y - 18 = 0$
Comparing this with the standard form $ax + by + c = 0$,we get:
$a = \pi$
$b = -3$
$c = -18$
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