Find the current through the branch ad of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The circuit is a Wheatstone bridge. Let the nodes be $a, b, c, d$. The resistances are $R_{ab} = 5 \, \Omega$,$R_{bc} = 10 \, \Omega$,$R_{ad} = 3

Vedclass · Accepted Answer

$1.1$

Vedclass · Answer

(C) The circuit is a Wheatstone bridge. Let the nodes be $a, b, c, d$. The resistances are $R_{ab} = 5 \, \Omega$,$R_{bc} = 10 \, \Omega$,$R_{ad} = 3 \, \Omega$,$R_{dc} = 6 \, \Omega$,and the central resistance $R_{bd} = 10 \, \Omega$.Check for the balanced condition: $\frac{R_{ab}}{R_{ad}} = \frac{5}{3}$ and $\frac{R_{bc}}{R_{dc}} = \frac{10}{6} = \frac{5}{3}$.Since $\frac{R_{ab}}{R_{ad}} = \frac{R_{bc}}{R_{dc}}$,the bridge is balanced.In a balanced Wheatstone bridge,the potential at node $b$ is equal to the potential at node $d$ $(V_b = V_d)$.Therefore,no current flows through the central branch $bd$.However,the question asks for the current through the branch $ad$. Since the branch $ad$ is in series with branch $dc$ (as $bd$ is effectively open),the total resistance of the lower path is $R_{lower} = 3 \, \Omega + 6 \, \Omega = 9 \, \Omega$.The voltage across the lower path is $10 \, V$.Thus,the current through the branch $ad$ is $I_{ad} = \frac{V}{R_{lower}} = \frac{10 \, V}{9 \, \Omega} \approx 1.11 \, A$.

Find the current through the branch $ad$ of the circuit shown in the figure. (in $, A$)

Similar Questions

What are the advantages of the null-point method in a Wheatstone bridge? What additional measurements would be required to calculate $R_{\text{unknown}}$ by any other method?

The current in the arm $CD$ of the circuit will be

For the circuit shown,with $R_1 = 1.0\,\Omega$,$R_2 = 2.0\,\Omega$,$E_1 = 2\,V$ and $E_2 = E_3 = 4\,V$,the potential difference between the points $a$ and $b$ is approximately (in $V$):

In a Wheatstone network,$P=2 \Omega, Q=2 \Omega, R=2 \Omega$,and $S=3 \Omega$. The resistance with which $S$ is to be shunted so that the bridge may be balanced is: (in $\Omega$)

The figure shows a portion of a circuit. What are the magnitude and direction of the current $i$ in the lower right-hand wire (in $A$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module