Find the $\text{l.c.m.}$ and $\text{g.c.d.}$ of the following by using the fundamental theorem of arithmetic: $96$ and $404$.

(N/A) Step $1$: Prime factorization of $96$:
$96 = 2^5 \times 3^1$
Step $2$: Prime factorization of $404$:
$404 = 2^2 \times 101^1$
Step $3$: The $\text{g.c.d.}$ is the product of the smallest power of each common prime factor:
$\text{g.c.d.}(96, 404) = 2^2 = 4$
Step $4$: The $\text{l.c.m.}$ is the product of the greatest power of each prime factor involved:
$\text{l.c.m.}(96, 404) = 2^5 \times 3^1 \times 101^1 = 32 \times 3 \times 101 = 9696$
Therefore,the $\text{g.c.d.}$ is $4$ and the $\text{l.c.m.}$ is $9696$.