Find the 20^{th} term of the A.P. -40, -15, 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given $A.P.$ is $-40, -15, 10, \ldots$Here,the first term $a = -40$.The common difference $d = -15 - (-40) = -15 + 40 = 25$.The formula for th

Vedclass · Accepted Answer

$435$

Vedclass · Answer

(D) The given $A.P.$ is $-40, -15, 10, \ldots$Here,the first term $a = -40$.The common difference $d = -15 - (-40) = -15 + 40 = 25$.The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.To find the $20^{th}$ term $(n = 20)$:$a_{20} = -40 + (20 - 1) 	imes 25$$a_{20} = -40 + 19 	imes 25$$a_{20} = -40 + 475$$a_{20} = 435$.Therefore,the $20^{th}$ term is $435$.

Find the $20^{th}$ term of the $A.P.$ $-40, -15, 10, \ldots$

Similar Questions

The $n^{th}$ term of the $A.P.$ $5, 10, 15, 20, \ldots$ is....... (in $n$)

Find the $10^{th}$ term of the $A.P.$ $\sqrt{2}, 3 \sqrt{2}, 5 \sqrt{2}, \ldots$ (in $\sqrt{2}$)

If the common difference of an $AP$ is $5,$ then what is $a_{18}-a_{13} ?$

For the finite $A.P.$ $3, 8, 13, \ldots, 253,$ find the $20^{th}$ term from the end.

The $10^{\text{th}}$ term of the $AP: 5, 8, 11, 14, \ldots$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module